EASY EXAMPLE.

Try to approximate
f(x)=x 2

with the synthesizer function
s(x)=a1+a2*x         a1,a2 being free parameters, we try to optimize in the
interval x = 0..b with error integral method.
Assume b ( upper range of interval ) as a free parameter.

Aha p = 1,2   (a1,a2)
You can start at the beginning, but it is easier to use (1)=(2) equation

b   b  
s ( x, ap )] * δs(ap)/δap dx= f(x)* δs(ap)/δap dx ,   p=0..n
a
(1)
a
(2)

we already have f(x) and s(x),

f(x)=x 2
s(x)=a1+a2*x

we have to compute ds(x) / da1 and ds(x) / da2 of s(x)=a1+a2*x :

ds(x) / da1 = 1 ( remember we are doing partial differentation to a1 )
ds(x) / da2 = x ( same for a2, its easy isnt it :-)

Now the equations stepping through p :

b   b  
(a1+a2*x)*1 dx= x 2*1 dx,    p=1
a
a
b   b  
(a1+a2*x)*x dx= x 2*x dx,    p=2
a
a

This can be written shorter in an matrix form:



We dont choose a special value for b !
Instead solving and optimizing the integral for all values of  b !!!

... leading to System:



Making some b,b**2 Division and using determinante

a1 = - b*b/6
a2 = b


So finally we have the SOLUTION:

s(x,b)=b*x - b*b/6      click to get a graph of the solution !

Thats for every b a very good approximation for f(x) =x**2 !


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